Question

A jet aircraft with a mass of 4,250 kg has an engine that exerts a force (thrust) equal to 60,100 N.

(a) What is the jet's acceleration when it takes off? (Give the magnitude.)
m/s2

(b)What is the jet's speed after it accelerates for 9 s? (Assume it starts from rest.)
m/s

(c) How far does the jet travel during the 9 s?
m

Answer 1

A. 14.14 m/s²

B. 127.26 m/s

C. 572.67 m

Step-by-step explanation:

From the question given above, the following data were obtained:

Mass (m) of jet = 4250 kg

Force (F) = 60100 N

A. Determination of the acceleration of the jet.

Mass (m) of jet = 4250 kg

Force (F) = 60100 N

Acceleration (a) =?

F = ma

60100 = 4250 × a

Divide both side by 4250

a = 60100 / 4250

a = 14.14 m/s²

B. Determination of the speed of the jet after 9 s.

Initial velocity (u) = 0 m/s

Acceleration (a) = 14.14 m/s²

Time (t) = 9 s

Final velocity (v) =?

v = u + at

v = 0 + (14.14 × 9)

v = 0 + 127.26

v = 127.26 m/s

C. Determination of the distance travelled during the time.

Initial velocity (u) = 0 m/s

Acceleration (a) = 14.14 m/s²

Time (t) = 9 s

Distance travelled (s) =?

s = ut + ½at²

s = (0 × 9) + (½ × 14.14 × 9²)

s = 0 + (7.07 × 81)

s = 0 + 572.67

s = 572.67 m.