Question

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the relationship between altitude and the boiling point of a liquid is linear. At an altitude of 8000 ft, the liquid boils at 204.4 DegreesF. At an altitude of 4500 ft, the liquid boils at 208.6 degrees F. Write an equation giving the boiling point b of the liquid, in degrees Fahrenheit, in terms of altitude a, in feet. What is the boiling point of the liquid at 2500 ft?

Answer 1

The answer to you question is,

We'll assume that the altitude is represented by the x-axis and that the boiling point is represented by the y-axis.

Explanation:

Trust me, and I already done this before

Answer 2

It's linear. So find the slope, with altitude as the x values and boiling point as the y values.

slope = (y2 - y1)/(x2 - x1) = (201.1 - 206.4)/(8500 - 4500) = -5.3/4000 = -0.001325 (degrees F per ft.)

Now set up the Point/Slope form of the equation and convert it to the Slope/Intercept form.

Y - 201.1 = -0.001325 * (X - 8500) Y = -0.001325 X + ( -11.2625 + 201.1 ) = -0.001325 X + 189.8375.

Set X = 2600 and solve for Y.

Oops; a mistake It should be Y = -0.001325 X + ( +11.2625 + 201.1 ) = -0.001325 X + 212.3625.

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Step-by-step explanation: I think I solved it but I'm confused.