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He population of a town with an initial population of 54,000 grows at a rate of 3.5​% per year.

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The population of the town after a certain number of years, with an initial population of 54,000 growing at a rate of 3.5% per year, can be calculated using the formula P(t) = 54,000 * (1 + 0.035)^t, where t represents the number of years.

To calculate the population of the town after a certain number of years with an initial population of 54,000 growing at a rate of 3.5% per year, we use the exponential growth formula:

P(t) = P0 * (1 + r)^t

where:

P(t) is the population after t years,

P0 is the initial population (54,000),

r is the growth rate (3.5% or 0.035 as a decimal),

t is the number of years.

Let's say we want to find the population after n years. Plugging in the values:

P(n) = 54,000 * (1 + 0.035)^n

This formula calculates the population after n years of growth. If, for instance, n = 10 years:

P(10) = 54,000 * (1 + 0.035)^10 ≈ 54,000 * 1.415 ≈ 76,410

Therefore, after 10 years, the population would be approximately 76,410.

Complete question should be:

What is the population of the town after a certain number of years if it initially had 54,000 people and is growing at a rate of 3.5% per year?

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