Question

when 14 gm of CO gas reacted with an excess amount of oxygen the volume of produced CO2 at STP is. ?​

Answer 1

22.4 liters

Step-by-step explanation:

1 Mole of gas occupies 22.4 Litres of volume at STP.

Given, the mass of CO=14 g

Molar mass of CO=12+16=28 g

No. of moles of CO=

28

14

​

=0.5 Moles

So, CO occupies 0.5×22.4=11.2 L at STP.