In this scenario, you applied the principles of trigonometry, specifically the tangent function, to determine the distance to the uncharted red dwarf star. The angle at point A (45°) and the angle at point B (90°) allowed you to set up a right triangle with the star as the vertex. The line of sight from the ship to the star (AB) served as the opposite side, and the distance traveled by the ship (BC) acted as the adjacent side.
Using the tangent function:
![\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \]](https://img.qammunity.org/2024/formulas/physics/high-school/b5n2eu5u7av3nk2s5oqks67901hh552tnp.png)
In this case:
![\[ \tan(45°) = \frac{\text{AB}}{\text{BC}} \]](https://img.qammunity.org/2024/formulas/physics/high-school/hdqphstjrfpvk3bs777m7tp1in56mtp7i1.png)
Solving for BC:
![\[ BC = \frac{\text{AB}}{\tan(45°)} \]](https://img.qammunity.org/2024/formulas/physics/high-school/30v31qaynlm5srahn8d5a56ef1x4yx80ka.png)
Given that AB is 125 million retemoliks, you could calculate BC, representing the distance to the star. This application of geometry and trigonometry allowed you to chart the position of the red dwarf star despite being out of sensor range.