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620<1200-0.05x<680 which compound in equitably inequality represents the range for the number of key presses answer choices are rounded to the nearest whole number

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Final answer:

To find the range for the number of key presses, we solve the compound inequality 620 < 1200 - 0.05x < 680 separately for each part and combine the results to get 10400 < x < 11600.

Step-by-step explanation:

The given compound inequality is 620 < 1200 - 0.05x < 680. To find the range for the number of key presses (x), we solve the inequality in two parts:

  1. 1200 - 0.05x > 620
  2. 1200 - 0.05x < 680

For the first part:

1200 - 0.05x > 620

-0.05x > 620 - 1200

-0.05x > -580

x < 580 / 0.05

x < 11600 (after dividing by -0.05, change the inequality direction)

For the second part:

1200 - 0.05x < 680

-0.05x < 680 - 1200

-0.05x < -520

x > 520 / 0.05

x > 10400 (after dividing by -0.05, change the inequality direction)

Combining the two parts, we get 10400 < x < 11600. This is the range for the number of key presses, rounded to the nearest whole number.

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