Question

How || A ball is thrown - Vertically up ward with avew city of 10m/s from below of a ball building The betony is 15m above to grownd find:-

A, the time required for the ball to hit the ground ?
B, the Velocity at the ball, when Just before it hits the ground?​

Answer 1

The time required for the ball to hit the ground is approximately 2.04 seconds. The velocity of the ball just before it hits the ground is approximately -10.07 m/s.

Step-by-step explanation:

To find the time required for the ball to hit the ground, we can use the kinematic equation for vertical motion:

Δy = v0t + 1/2gt2

Where Δy is the displacement (15m), v0 is the initial velocity (10m/s), t is the time, and g is the acceleration due to gravity (-9.8m/s2). Rearranging the equation gives:

t = (√(v02 + 2gΔy) - v0) / g

Substituting the values:

t = (√(102 + 2 * -9.8 * 15) - 10) / -9.8

Calculating, we get:

t ≈ 2.04 seconds

To find the velocity of the ball just before it hits the ground, we can use the equation:

v = v0 + gt

Substituting the values:

v = 10 - 9.8 * 2.04

≈ -10.07 m/s