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In an electric field the work done for bringing 5 coulomb charges from infinity to a point A is 50 J and in bringing the same charge to some another point B is 50 J. What is the potential difference between points A and B?

Group of answer choices

0 V.

5 V.

6 V.

8 V.

1 Answer

6 votes

Final answer:

The potential difference between points A and B is 0 volts because the work done to move a 5 coulomb charge to each point from infinity is the same (50 J), indicating no change in potential energy.

Step-by-step explanation:

The work done to move a charge in an electric field is related to the electric potential difference between two points. Since the work done to bring a charge of 5 coulombs from infinity to point A is 50 J and the same amount of work is done to bring the same charge to point B, the potential energy at both points for this charge is the same. Therefore, there is no change in potential energy when moving the charge from point A to point B and hence, the potential difference between points A and B is 0 V.

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