Question

a double-slit experiment has slit spacing 0.032 mm , slit-to-screen distance 1.7 m , and wavelength 490 nm . part a what's the phase difference between two waves arriving at a point 0.56 cm from the center line of the screen? express your answer in degrees,

Answer 1

To find the phase difference in a double-slit experiment, you can use the formula (2π * d * sinθ) / λ, where d is the slit spacing, θ is the angle from the center line to the point on the screen, and λ is the wavelength.

Step-by-step explanation:

To find the phase difference between two waves arriving at a point 0.56 cm from the center line of the screen in a double-slit experiment, we can use the formula:

Phase Difference (in degrees) = (2π * d * sinθ) / λ

Where d is the slit spacing, θ is the angle from the center line to the point on the screen, and λ is the wavelength. In this case, the slit spacing (d) is 0.032 mm, the angle (θ) can be found using trigonometry, and the wavelength (λ) is 490 nm.

After finding the angle, plug the values into the formula to calculate the phase difference in degrees.