Question

What is the reynolds number re for blood leaving the heart through the aorta if the diameter of the aorta is 2.15 cm and the blood has a dynamic viscosity of 2.70 x 10⁻³ pa, a density of 1050 kg/m³ and travels at a mean fluid velocity of 30.7 cm/s?

Answer 1

The Reynolds number (Re) for blood leaving the heart through the aorta is approximately 221824.07.

Step-by-step explanation:

The Reynolds number (Re) for blood leaving the heart through the aorta can be calculated using the formula:

Re = (density * velocity * diameter) / viscosity

Given:
Diameter of the aorta = 2.15 cm = 0.0215 m
Blood dynamic viscosity = 2.70 x 10⁻³ Pa·s
Blood density = 1050 kg/m³
Mean fluid velocity = 30.7 cm/s = 0.307 m/s

Plugging in these values, we can find:

Re = (1050 * 0.307 * 0.0215) / (2.70 x 10⁻³)

Simplifying the equation gives:

Re = 221824.07

Therefore, the Reynolds number for blood leaving the heart through the aorta is approximately 221824.07.