Final answer:
The effective access time for a paged memory management system with a main memory access time of 500 ns and cache access time of 5 ns with an 80% hit ratio is 105 ns.
Step-by-step explanation:
The question is asking to calculate the effective access time for a paged memory management system. In a system where memory access involves a cache, you often have to consider both the cache access time and the main memory access time, factoring in the hit ratio (the percentage of time that the data is found in the cache). The formula for calculating the effective access time is as follows:
Effective Access Time = (Cache Hit Ratio) × (Cache Access Time) + ((1 - Cache Hit Ratio) × (Miss Penalty))
With a main memory access time of 500 ns, a cache access time of 5 ns, and a cache hit ratio of 80%, the effective access time can be calculated as:
Effective Access Time = (0.80 × 5 ns) + (0.20 × (5 ns + 500 ns))
= (0.80 × 5 ns) + (0.20 × 505 ns)
= (4 ns) + (101 ns)
= 105 ns
In a paged memory management system like this, the effective access time would be 105 ns.