Final answer:
The heat transfer required to raise the temperature of 500 g of water from 20°C to 30°C is 20920 J or 20.92 kJ, using the specific heat capacity of water, which is 4.184 J/g°C.
Step-by-step explanation:
To calculate the heat transfer necessary to raise the temperature of 500 g of water from 20°C to 30°C, we need to use the concept of specific heat capacity. The specific heat capacity of water is a constant value, 4.184 J/g°C, which tells us how much heat is required to raise the temperature of 1 g of water by 1°C.
The formula to calculate heat transfer (Q) is Q = m · c · ΔT. Here, 'm' represents the mass of the water, 'c' is the specific heat capacity of water, and 'ΔT' is the change in temperature.
Plugging in the values: Q = 500 g · 4.184 J/g°C · (30°C - 20°C) = 500 g · 4.184 J/g°C · 10°C = 20920 J.
Therefore, the amount of heat required to raise the temperature of 500 g of water by 10°C is 20920 J or 20.92 kJ.