Final answer:
Using the ideal gas law, it can be calculated that approximately 14.29 millimoles of CF₂Cl₂ would be released 1980s Aquanet hairspray, given the can contains 4.0 floz at 3.0 atm and 25 °C.
Step-by-step explanation:
It contains 4.0 fl oz of CF₂Cl₂ at 3.0 atm and 25 °C. To answer this, we use the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature in Kelvin.
First, convert 4.0 fl oz to mL using the conversion factor 1 fl oz = 29.57 mL: 4.0 fl oz × 29.57 mL/fl oz = 118.28 mL. Convert milliliters to liters (L) by dividing by 1000: 118.28 mL / 1000 = 0.11828 L. For T, convert °C to Kelvin (K): 25 °C + 273.15 = 298.15 K. Now, we can solve for n (number of moles): n = (PV)/(RT).
Using R = 0.0821 L·atm/mol·K, we get: n = (3.0 atm × 0.11828 L) / (0.0821 L·atm/mol·K × 298.15 K). n ≈ 0.01429 mol. To get the amount in millimoles, multiply moles by 1000: 0.01429 mol × 1000 mmol/mol ≈ 14.29 mmol. Therefore, approximately 14.29 millimoles of CF₂Cl₂ would be released.