Final answer:
The fare from Rawalpindi to Islamabad is Rs. 130, and the fare from Rawalpindi to Murree is Rs. 170. This is calculated by forming and solving a system of linear equations.
Step-by-step explanation:
The question involves solving a system of linear equations to find the cost of bus tickets from Rawalpindi to Islamabad and from Rawalpindi to Murree. Let's denote the cost of a ticket from Rawalpindi to Islamabad as x and from Rawalpindi to Murree as y. We have two equations based on the given information:
• 2x + 3y = 770
• 3x + 2y = 730
Now, we will solve this system using the method of substitution or elimination. Let's multiply the first equation by 3 and the second equation by 2 to eliminate y:
• 6x + 9y = 2310
• 6x + 4y = 1460
Subtracting the second equation from the first gives us:
5y = 850
Dividing both sides by 5 yields:
y = 170
Now that we have the value for y, we can substitute it back into either of the original equations to find x. Let's use the first equation:
2x + 3(170) = 770
2x + 510 = 770
2x = 260
x = 130
The fare from Rawalpindi to Islamabad (x) is Rs. 130, and the fare from Rawalpindi to Murree (y) is Rs. 170.