Final answer:
The question requires using a water property table and thermodynamic principles to find temperature, volume, and quality of water at given internal energy and pressure. With only internal energy and pressure, the phase of water cannot be determined without additional data or using the saturation tables for water.
Step-by-step explanation:
The question pertains to thermal physics and involves finding the temperature, volume, and quality of 1 kg water given its internal energy (U) is 3000 Kj/kg and pressure (P) is 0.3 MPa. Since the specific internal energy and pressure are provided, we may reference a water property table or use thermodynamic relations to solve the problem, as it is a matter of thermodynamics which is a branch of physics.
By comparing the given internal energy with the data in the water property table for 0.3 MPa, we can determine whether the water is in the liquid phase, the vapor phase, or in a mixture phase (liquid-vapor). If it is a mixture, we would define the quality (x) as the ratio of the mass of the vapor to the total mass.
Unfortunately, without the specific temperature or more specific information about the phase, such as using the saturation tables directly, we cannot explicitly solve the problem with the provided information alone. The formula mentioned, Uw = (331 m/s)₁ (ᵣ₃₀₃ Kᵽ₂₇₃ K), seems to be related to the speed of sound in water but is not directly applicable here.