49.2k views
5 votes
If n (A) = 20, n (B) = 28 and n (AB) = 36 then n (A B) = ?

User Nunchucks
by
7.7k points

1 Answer

6 votes

Final answer:

The student's question contained a typo but likely refers to finding the number of elements in the union of two sets. Assuming they meant n(A ∪ B), by applying the principle of inclusion-exclusion, the answer is calculated to be 12.

Step-by-step explanation:

The question seems to be based on a typo since n (A B) is not a standard mathematical notation when referring to sets or numbers of elements in sets. However, it is possible that the student might be asking about the principle of inclusion-exclusion or maybe the union or intersection of sets. One common interpretation of the question could be finding n(A ∩ B), which represents the number of elements in the intersection of sets A and B.

Assuming that n (A ∩ B) = 36 represents the number of elements in the intersection of sets A and B, and we want to find n(A ∪ B), which is the number of elements in the union of sets A and B, we can use the principle of inclusion-exclusion:

n(A ∪ B) = n(A) + n(B) - n(A ∩ B)

Substituting the given values:

n(A ∪ B) = 20 + 28 - 36 = 12

Therefore, the number of elements in the union of sets A and B is 12.

User Lasitha Yapa
by
8.1k points