Question

Human body temperatures have a mean of 98.20° F and a standard deviation of 0.62° F. If a student is found to have a temperature of 99.5° F, find the z score and assess whether this temperature should be considered unusual.

O -2.1; not unusual
O 2.1; not unusual
O -2.1: unusual
O 2.1; unusual

Answer 1

The z score of a student's body temperature of 99.5° F, given a mean of 98.20° F and a standard deviation of 0.62° F, is approximately 2.10, which is considered unusual as it is more than two standard deviations away from the mean.

"The correct option is approximately option D"

Step-by-step explanation:

To calculate the z score for the student's body temperature, we use the formula:

Z = (X - μ) / σ

Where X is the value in question (the student's temperature), μ is the mean, and σ is the standard deviation. Plugging in the values:

Z = (99.5° F - 98.2° F) / 0.62° F

Z ≈ 2.10

A z score of 2.10 is more than two standard deviations away from the mean, which generally indicates that the value is unusual in a normal distribution. In this context, a body temperature of 99.5° F would be considered unusual, although it is important to note that human body temperature can normally vary and still be within a healthy range, as previously discussed.