52.7k views
1 vote
The system of equations y = negative one-half x + 4 and y = 2x – 1 is shown on the graph below. On a coordinate plane, 2 lines intersect at (2, 3). According to the graph, what is the solution to this system of equations?

a. (2, 3)
b. (3, 2)
c. (–1, 4)
d. (4, –1)

1 Answer

3 votes

Final answer:

The solution to the system of equations y = -½x + 4 and y = 2x – 1, which intersect at a point on the graph, is (2, 3). The correct answer is option (a).

Step-by-step explanation:

The system of equations given by y = -½x + 4 and y = 2x – 1 intersects at a point on the graph. This point represents the solution to the system of equations, where both equations have the same x and y values. According to the information provided, the lines intersect at the point (2, 3). This means that when x is 2, both equations will yield a y-value of 3. Since this is the point of intersection, the correct solution to the system of equations is (2, 3).

To verify, we can substitute x with 2 in both equations and see if we get y as 3. For the first equation:

  • y = -½(2) + 4 = -1 + 4 = 3

And for the second equation:

  • y = 2(2) - 1 = 4 - 1 = 3

Since both equations yield a y-value of 3 when x is 2, this confirms that the solution (2, 3) is correct for the system.

User Sapanda
by
7.9k points