Question

How many moles of KCl are contained in each of the following?

Part A. 0.589 L of a 2.3 M KCl solution

Part B. 1.4 L of a 0.90 M KCI solution

Part C. 116 mL of a 1.85 M KCl solution

Answer 1

The number of moles of KCl in the solutions for Part A, B, and C were calculated by multiplying the volume in liters by the molarity, yielding 1.3547, 1.26, and 0.2146 moles respectively.

Step-by-step explanation:

The student has asked to calculate the number of moles of KCl in different solutions with varying volumes and molarities.

Part A:

To find the number of moles of KCl in a 0.589 L of a 2.3 M KCl solution, use the formula moles = molarity × volume. So,
moles = 2.3 mol/L × 0.589 L = 1.3547 moles of KCl.

Part B:

For 1.4 L of a 0.90 M KCl solution,
moles = 0.90 mol/L × 1.4 L = 1.26 moles of KCl.

Part C:

For 116 mL (or 0.116 L) of a 1.85 M KCl solution,
moles = 1.85 mol/L × 0.116 L = 0.2146 moles of KCl.

To summarize, by multiplying the molarity by the volume in liters, we calculated the number of moles of KCl in each solution:

Part A: 1.3547 moles

Part B: 1.26 moles

Part C: 0.2146 moles