5.8k views
2 votes
A ball of mass 5.0 kg is suspended by two wires from a horizontal arm that is attached to a vertical shaft, as shown in the figure. The shaft is in uniform rotation about its axis. The rate of rotation is adjusted until the tensions in the two wires are equal. At that speed, the radial acceleration of the ball is closest to

(a) 4.9 m/s²
(c) 6.9 m/s²
(b) 5.9 m/s²
(d) 7.9 m/s²​

User Volkovs
by
7.9k points

1 Answer

6 votes

Final answer:

The radial acceleration of the ball cannot be calculated without specific values for angular velocity and radius. However, for an object with known values, such as an angular velocity of 5 rad/s and a radius of 0.2 m, the radial acceleration would be 5 m/s², which relates to the concept involved in the original question.

Step-by-step explanation:

To calculate the radial acceleration of the ball in the original question, we use the formula for centripetal acceleration a = ω2×r, where ω is the angular velocity and r is the radius of the circular path.

Without the explicit values for ω and r, we cannot provide a complete calculated answer.

However, for a related scenario such as calculating the centripetal acceleration for an object with a given angular velocity and radius, if we consider an object following a path with a radius of curvature of 0.2 m and at an angular velocity of 5 rad/s, we can plug these values into the formula to get a = 52 × 0.2 m = 5 m/s2.

Therefore, the radial acceleration of such an object would be closest to option (d) 5 m/s2.

User Kris Jobs
by
8.0k points