Final answer:
The correct answer is c. 900 g water.
Step-by-step explanation:
To calculate the amount of water produced from the reaction of hydrogen and oxygen, we first determine the limiting reactant. We use the molar mass of hydrogen (H₂) which is approximately 2.016 g/mol and oxygen (O₂) which is 32 g/mol. The balanced chemical equation is:
2 H₂(g) + O₂(g) → 2 H₂O(l)
Hydrogen: 120 g H₂ × (1 mol H₂ / 2.016 g H₂) = 59.52 mol H₂
Oxygen: 800 g O₂ × (1 mol O₂ / 32 g O₂) = 25 mol O₂
According to the stoichiometry of the reaction, each mole of O₂ reacts with 2 moles of H₂. Therefore, O₂ is the limiting reactant. The amount of H₂O produced is therefore:
25 mol O₂ × (2 mol H₂O / 1 mol O₂) × (18.02 g H₂O / 1 mol H₂O) = 900g H₂O
The maximum amount of water that can be produced is 900 grams.