Question

If an object with a temperature of 383 k and emissivity of 0.802 radiates at 570 w, what is its area? type your answer here m²

Answer 1

Using the Stefan-Boltzmann law, the surface area of an object with a temperature of 383 K, an emissivity of 0.802, and radiating at 570 W is calculated to be approximately 0.022 m².

Step-by-step explanation:

To calculate the surface area of an object based on its temperature, emissivity, and the power it radiates, we use the Stefan-Boltzmann law:

Power (P) = ε73;eAT'⁴

Where:

• ε is the emissivity of the material (dimensionless),
• A is the surface area in meters squared (m²),
• T' is the temperature in Kelvin (K), and
• ε is the Stefan-Boltzmann constant (5.67 x 10⁻⁸ J/s · m² K⁴).

Given that the object is radiating 570 W, has an emissivity of 0.802, and a temperature of 383 K, we can rearrange the formula to solve for A:

A = P / (ε73;eT'⁴)

Substituting the given values:

A = 570 W / (5.67 x 10⁻⁸ J/s · m² K⁴ · 0.802 · (383 K)⁴)

After performing the calculation, we find that the surface area A is approximately:

A = 0.022 m²