Question

A 1020-kg compact car is moving along the highway at 31.9 m/s when the driver abruptly brakes for 2.08 seconds. an average braking force of 4250 n is exerted upon the car to slow it down. determine the loss of momentum of the car during the braking period. (enter it as a value.)

Answer 1

The loss of momentum of the car during the braking period, when an average braking force of 4250 N is exerted for 2.08 seconds, is calculated to be 8840 N·s.

Step-by-step explanation:

The question is about calculating the loss of momentum of the car during the braking period when a known force is applied for a specific duration.

To find the lost momentum, we can apply the formula for impulse, which is the change in momentum and is equal to the force applied multiplied by the time the force is applied (Impulse = Force × Time).

In this case, the braking force is 4250 N and the time is 2.08 seconds.

Using the formula, the impulse and hence the loss of momentum would be:

Impulse = Force × Time
Impulse = 4250 N × 2.08 s
Impulse = 8840 N·s

This is the loss of momentum of the car due to braking.