Question

A 4.2 l volume of ideal neon gas (monatomic) is at a pressure of 3.3 atmospheres and a temperature of 450k. the atomic mass of neon is 20.2 g/mol. the number of neon atoms in the gas is what?

Answer 1

The calculated number of neon atoms in the gas is approximately 2.04 x 10^23 atoms.

Step-by-step explanation:

To determine the number of neon atoms in the gas, we can use the ideal gas law equation:

PV = nRT

Where:

• P is the pressure in atmospheres (3.3 atm)
• V is the volume in liters (4.2 L)
• n is the number of moles of gas
• R is the ideal gas constant (0.0821 L·atm/mol·K)
• T is the temperature in Kelvin (450K)

Solving for n, we can rearrange the equation to:

n = PV / RT

Substituting the given values, we have:

n = (3.3 atm)(4.2 L) / (0.0821 L·atm/mol·K)(450K) = 0.338 moles

Since 1 mole of any substance contains 6.022 x 10^23 particles (Avogadro's number), we can calculate the number of neon atoms:

Number of atoms = n x (6.022 x 10^23)

Number of atoms = 0.338 moles x (6.022 x 10^23 atoms/mole) ≈ 2.04 x 10^23 neon atoms