36.2k views
3 votes
30.0 grams of argon and 15.0 grams of xenon are placed in a 120.0 ml container at 22.0 C. The partial pressure of xenon in _____ atm

1 Answer

3 votes

Final answer:

To find the partial pressure of xenon in the container, we need to calculate the total number of moles of gas in the container. Given the masses of argon and xenon and their molar masses, we can calculate the number of moles of each gas. Using Dalton's law of partial pressures, we can then calculate the partial pressure of xenon.

The partial pressure of xenon is: Partial pressure of xenon = 0.132 * 1.00 atm = 0.132 atm

Step-by-step explanation:

To find the partial pressure of xenon in the container, we first need to calculate the total number of moles of gas in the container. Given that the container has a volume of 120.0 ml and is filled with 30.0 grams of argon and 15.0 grams of xenon, we can calculate the number of moles of each gas using their respective molar masses.

Molar mass of argon (Ar) = 39.95 g/mol

Molar mass of xenon (Xe) = 131.29 g/mol

Number of moles of argon = mass of argon / molar mass of argon = 30.0 g / 39.95 g/mol = 0.751 moles

Number of moles of xenon = mass of xenon / molar mass of xenon = 15.0 g / 131.29 g/mol = 0.114 moles

Now, we can calculate the partial pressure of xenon using Dalton's law of partial pressures.

Partial pressure of xenon = mole fraction of xenon * total pressure

Mole fraction of xenon = number of moles of xenon / total number of moles = 0.114 moles / (0.751 moles + 0.114 moles) = 0.132

Given that the total pressure is 1.00 atm, the partial pressure of xenon is: Partial pressure of xenon = 0.132 * 1.00 atm = 0.132 atm

User Anarki
by
7.1k points