Final answer:
To calculate the acceleration of a 155kg block of ice being dragged by a chain at an angle, one must find the horizontal component of the applied force, adjust for friction using the coefficient of friction, and apply Newton's second law to find the acceleration.
Step-by-step explanation:
The student's question involves calculating the acceleration of a 155kg block of ice being pulled by a chain. To find the acceleration, we need to consider the net force acting on the block. The force exerted by the chain has two components due to its angle: a horizontal component that helps to move the block and a vertical component that slightly reduces the normal force (and thus the friction force). With a coefficient of friction of 0.25, the force of friction can be calculated. The net force will then be the horizontal component of the pulling force minus the frictional force. Lastly, using Newton's second law (F=ma), we can solve for the acceleration.
Let's break this down:
- First, find the horizontal component of the pulling force: Fhorizontal = 544N * cos(250).
- Calculate the normal force considering the weight of the block and the vertical component of the pulling force: Normal force = (155kg * 9.8m/s2) - (544N * sin(250)).
- Determine the force of friction using the normal force and the coefficient of friction: Frictional force = Normal force * 0.25.
- Compute the net force, which is Fhorizontal minus the frictional force.
- Finally, the acceleration is found by dividing the net force by the mass: Acceleration = Net force / 155kg.
By following these steps, the student can calculate the acceleration of the block of ice.