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Identify the base in the following acid-base reaction. NaNO₂(aq) + HI(aq) → Nal(aq) + HNO₂(aq)

a. Na⁺
b. HNO₂
с. I⁻
d. HI
e. NO₂⁻

User Exscape
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1 Answer

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Final answer:

In the reaction NaNO₂(aq) + HI(aq), the base is NO₂⁻ because it accepts a proton to form HNO₂. This adheres to the Brønsted-Lowry definition of a base as a proton acceptor. So the correct answer is E.

Step-by-step explanation:

In the acid-base reaction NaNO₂(aq) + HI(aq) → NaI(aq) + HNO₂(aq), the base is the species that accepts a proton (H+). According to the Brønsted-Lowry theory, the base is defined as a proton acceptor.

In this reaction, the sodium nitrite (NaNO₂) dissociates in water to form Na+ and NO₂⁻ ions. The compound that accepts the proton here is the NO₂⁻ ion, as it gains a proton from HI to form HNO₂.

Therefore, the correct answer is e. NO₂⁻.

Here are a couple of examples of neutralization reactions and partial ionization:

  • Neutralization reactions: HNO₃(aq) + Ba(OH)₂(aq) → Ba(NO₃)₂(aq) + 2H₂O(l)
  • Partial ionization: HNO₂(aq) → H+(aq) + NO₂⁻(aq)

User Neil Turner
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