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Cyclist with a mass of 80 kg is riding around a circular track with a radius of 100 m, and is traveling at 6.5 m/s. what is the cyclist's centripetal acceleration?

A) 0.084 m/s²
B) 0.525 m/s²
C) 8.416 m/s²
D) 525.000 m/s²

User SrinR
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1 Answer

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Final answer:

The centripetal acceleration of a cyclist moving at a speed of 6.5 m/s around a circular track with a radius of 100 m is calculated using the formula a = v^2/r and results in an acceleration of 0.4225 m/s², which is rounded to 0.42 m/s² for this context. This is not reflected in any of the multiple-choice options explicitly, but the closest option is: B) 0.525 m/s2

Step-by-step explanation:

The question involves calculating the centripetal acceleration of a cyclist moving in a circular path. To find the centripetal acceleration, we can use the formula a = v^2/r, where a is the centripetal acceleration, v is the velocity, and r is the radius of the circular path.

In this problem, the cyclist is traveling at a speed of 6.5 m/s around a circular track with a radius of 100 m. Plugging these values into the formula, we get:

a = (6.5 m/s)2 / 100 m = 42.25 m2/s2 / 100 m = 0.4225 m/s2

This acceleration is rounded to three significant figures, as 0.425 m/s2. However, due to the options provided, we will round it to two decimal places, making it 0.42 m/s2.

User Brett Walker
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