Question

Under identical conditions, gaseous co₂ and ccl₄ are allowed to effuse through a pinhole. if the rate of effusion of the co₂ is 0.063 mol/s, what is the rate of effusion of the ccl₄?

a) 0.063 mol/s
b) 0.22 mol/s
c) 0.018 mol/s
d) 0.034 mol/s
e) 0.12 mol/s

Answer 1

Using Graham's law of effusion, the rate of effusion of CCl₄ was calculated to be approximately 0.018 mol/s, which is option (c).

Step-by-step explanation:

The question involves the application of Graham's law of effusion, a fundamental concept in chemistry. Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. This relationship can be expressed as:

Rate of effusion of gas 1 / Rate of effusion of gas 2 = sqrt(Molar mass of gas 2 / Molar mass of gas 1)

We are given that CO₂ (₄₄.01 g/mol) effuses at a rate of 0.063 mol/s and we need to find the rate of effusion for CCl₄, which has a molar mass of about 153.81 g/mol.

Using the above formula, we substitute the known values:

Rate of effusion of CCl₄ / 0.063 mol/s = sqrt(44.01 g/mol / 153.81 g/mol)

Solving for the rate of effusion of CCl₄:

Rate of effusion of CCl₄ = 0.063 mol/s * sqrt(44.01 / 153.81)

After calculating the square root and multiplying, we find the rate of effusion for CCl₄ to be approximately

0.018 mol/s, which corresponds to option (c).