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If we had a commercial air handler and we need to know the speed of the blower if the pulley on the five horse power 3450 rpm motor is 6" and the pulley on a 2" fifteen foot drive shaft is 10", what would be the rpm of the blower?

A. 3450 rpm
B. 2070 rpm
C. 1725 rpm
D. 863 rpm

1 Answer

3 votes

Final answer:

Using a pulley ratio to calculate the blower rpm, the result is 5750 rpm, which does not match any of the given answer options. A reevaluation of the question might be required.

Step-by-step explanation:

To determine the blower's rpm (rotations per minute), we can use the concept of pulley ratios. The ratio of the motor pulley to the drive shaft pulley determines the change in rpm from the motor to the blower. Given that the motor has a 6" pulley and rotates at 3450 rpm, and the drive shaft has a 10" pulley, we calculate the new rpm by setting up a proportional relationship:

  • RPM of motor / Diameter of motor pulley = RPM of blower / Diameter of drive shaft pulley
  • 3450 rpm / 6" = x rpm / 10"
  • To find x (rpm of the blower), we cross multiply and solve for x:
  • x * 6" = 3450 rpm * 10"
  • x = (3450 rpm * 10") / 6"
  • x = 5750 rpm

However, none of the provided answer options (A. 3450 rpm, B. 2070 rpm, C. 1725 rpm, D. 863 rpm) match the calculated rpm. It is necessary to review the question and perform the calculations again if there is any possibility of an error.

User Guy Brooker
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