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write the slope intercept form of an equation though given points
through (-1, 1) and (-2, -3)

User Nicolas Buquet
by
2.8k points

2 Answers

14 votes
14 votes


\huge\boxed{y=4x+5}

The slope intercept form.


\huge\begin{array}{ccc}y=mx+b\end{array}


m - the slope


b - y-intercept

The two point form:


\huge\begin{array}{ccc}y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)\end{array}

We have two points:


A(-1,\ 1)\to x_1=-1,\ y_1=1\\\\B(-2,-3)\to x_2=-2,\ y_2=-3

Substitute:


y-1=(-3-1)/(-2-(-1))(x-(-1))\\\\y-1=(-4)/(-2+1)(x+1)\\\\y-1=(-4)/(-1)(x+1)\\\\y-1=4(x+1)

Use the Distributive Property:


a(b+c)=ab+ac


y-1=4x+4

add 1 to both sides


\huge\boxed{y=4x+5}

User Aleksy Goroszko
by
3.5k points
12 votes
12 votes

Answer:

y = 4x + 5

Explanation:

change in y ÷ change in x = gradient

-3 - 1 = -4

-2 - -1 = -1

-4 ÷ -1 = 4

gradient = 4

equation of a line

y = mx + c

substitue values

-3 = -2(4) + c

-3 = -8 + c

5 = c

confirmation of c

1 = -1(4) + c

1 = -4 + c

5 = c (same value for c = correct)

put into equation of a line

y = 4x + 5

User Jagesh Maharjan
by
2.8k points
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