Question

When calling superclass constructor from the subclass constructor using super(), the number of parameters of the subclass constructor and those in super() must match. (True or False)

Answer 1

In Java, the number of parameters in the subclass constructor and the superclass constructor do not have to match when using super().

Step-by-step explanation:

In Java, when calling a superclass constructor from the subclass constructor using super(), the number of parameters of the subclass constructor and those in super() do not have to match. They can be different.

Let's take an example:

public class Animal {
public Animal(String name) {
// superclass constructor
}
}

public class Dog extends Animal {
public Dog(String name, int age) {
super(name); // calling superclass constructor with one parameter
// subclass constructor
}
}

In the above example, the superclass constructor in the Animal class takes one parameter (name), while the subclass constructor in the Dog class takes two parameters (name and age). By using super(name), we are correctly calling the superclass constructor from the subclass constructor.