Final answer:
To achieve a 3.0 ppm chlorine concentration in a 21,200 kg (5,000-gallon) pool, 63.6 grams of chlorine is required.
Step-by-step explanation:
When chlorinating water to eliminate known hazardous contaminants, a certain residual level of chlorine must be maintained. In general, water systems should achieve a chlorine residual of at least 1 ppm, but the exact requirement can vary based on regulations and the specific conditions of the water system. However, if we want to achieve a chlorine concentration of 3.0 ppm in a 5,000-gallon pool (which is equivalent to 21,200 kg of water), we can calculate the mass of chlorine to be added as follows:
Firstly, know that 1 ppm is equivalent to 1 milligram of substance per kilogram of water (mg/kg). To reach a concentration of 3.0 ppm in 21,200 kg of water, you would need:
3.0 ppm * 21,200 kg = 63,600 mg of chlorine.
Since there are 1,000 mg in a gram, this can be converted to grams:
63,600 mg / 1,000 = 63.6 grams of chlorine.
Therefore, to achieve a chlorine concentration of 3.0 ppm in a 5,000-gallon pool, one must add 63.6 grams of chlorine.