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Explain, using examples, the relationship between ligand binding affinity and the equilibrium dissociation constant Kd

- what does Kd refer to?
- small Kd indicates?
- large Kd indicates?

example for tight binding
biotin deficiency?

User Tim Moore
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1 Answer

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Final answer:

The equilibrium dissociation constant, Kd, represents the strength of the ligand-receptor interaction. A small Kd indicates a tight binding affinity, while a large Kd indicates a weak binding affinity. In the case of biotin deficiency, a small Kd value means that only a small amount of biotin is needed to form biotin-receptor complexes.

Step-by-step explanation:

The equilibrium dissociation constant, Kd, is a measure of the strength of the interaction between a ligand and its receptor. It represents the concentration of the ligand at which half of the receptor binding sites are occupied.

A small Kd indicates a tight binding affinity, meaning that a low concentration of ligand is required to form a significant amount of ligand-receptor complex. For example, in the case of biotin deficiency, biotin (ligand) has a high affinity for biotin receptors, so a small Kd value indicates that only a small amount of biotin is needed to form a biotin-receptor complex.

On the other hand, a large Kd indicates a weak binding affinity, meaning that a high concentration of ligand is required to form a significant amount of ligand-receptor complex. Using the same example, if the Kd value for biotin receptors was large, it would take a large amount of biotin to form enough biotin-receptor complexes to trigger the biological response.

User Cordsen
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