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If the force of static friction on a crate is 67 N and the weight of the create is 289 N, what is the coefficient of static friction?

a
19363
b
0.23
c
4.31
d
222

User Gmajivu
by
6.1k points

1 Answer

4 votes

Answer:

B) μ = 0.23

Step-by-step explanation:

The coefficient of friction is equal to μ = F / N where μ (mu) is the coefficient of friction, F is the friction force, and N is the normal force (the force of an object being applied onto the earth by gravity).

F, the friction force, is given as 67 N

Since the weight of the crate is 289 N, that means the normal force is 289 N.

This means that the coefficient of friction is μ = F / N = 67 N / 289 N = 0.23183391 = 0.23

Therefore, B is the correct answer

User Tbxfreeware
by
5.1k points