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X = 1

y = 2
def swap(x, y):
tmp = x
x = y
y = tmp
swap(x, y)
print(x)
print(y)
What is the output?
a) 1 2
b) 2 1
c) 1 1
d) 2 2

1 Answer

0 votes

Final answer:

The output of the Python code provided will be 1 and 2 because the swap function only changes the values of x and y within its own scope, leaving the original variables outside the function unaffected.

Step-by-step explanation:

The code provided is an example of a function in Python that intends to swap the values of two variables x and y. However, due to the scope of the variables inside the function, the swap does not affect the external variables. The output of this code will be:

1
2

When the swap function is called, it swaps the values of x and y only within the scope of the function. The original variables x and y defined before the function call remain unchanged. Thus, when we print x and y outside the function, we get their initial values.

User Dzikoysk
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