Final answer:
The output of the Python code provided will be 1 and 2 because the swap function only changes the values of x and y within its own scope, leaving the original variables outside the function unaffected.
Step-by-step explanation:
The code provided is an example of a function in Python that intends to swap the values of two variables x and y. However, due to the scope of the variables inside the function, the swap does not affect the external variables. The output of this code will be:
1
2
When the swap function is called, it swaps the values of x and y only within the scope of the function. The original variables x and y defined before the function call remain unchanged. Thus, when we print x and y outside the function, we get their initial values.