Question

While performing the hangtime experiment a student jumps and gets a hangtime of 0.43 seconds. How high was their jump in meters? Assume gravity is 10 m/s^2.

Answer 1

To calculate the height of a student's jump with a hangtime of 0.43 seconds, we use kinematic equations and find that the height is approximately 0.6925 meters.

Step-by-step explanation:

When a student jumps and has a hangtime of 0.43 seconds, we use kinematic equations to calculate the height of the jump, assuming gravity is 10 m/s2. During the jump, the time going up is equal to the time coming down, so the total hangtime is twice the time it takes to reach the apex of the jump. Therefore, the time to reach the highest point is 0.215 seconds (half of 0.43 seconds). We use the following kinematic equation to find the height (h) of the jump:

h = v0t + (1/2)gt2

At the highest point, the final velocity (v) is 0 m/s. Rearranging the equation to solve for the initial velocity (v0) we get:

v0 = gt

Substituting the values we get:

v0 = (10 m/s2)(0.215 s) = 2.15 m/s

Now we can calculate height:

h = (2.15 m/s)(0.215 s) + (1/2)(10 m/s2)(0.215 s)2

h = 0.46125 m + 0.23125 m

h = 0.6925 m

Therefore, the height of the student's jump is approximately 0.6925 meters.