Final answer:
The question covers the motion of a two-block system with one block on a frictionless surface connected to a hanging block over a pulley. The acceleration of the system, the time for the hanging block to hit the ground, the motion of both blocks, and the distance between their landing points are addressed.
Step-by-step explanation:
This physics problem addresses a system where two blocks are connected by a string passing over a pulley, with one block on a table (mass m) and one block hanging (mass m). We can solve this system step by step for each part of the question:
- Acceleration of Block B: The only forces acting on block B are its weight (mg) downward and the tension T upward from the string connecting it to block A. Since block A is on a frictionless surface, the tension is the same throughout the string, and there is no force opposing the motion due to friction. Therefore, the net force on block B is simply mg - T, and this will cause block B to accelerate downwards. We must also consider block A, which has a net force of T acting to the right. Since both blocks are connected by a string of constant length, they must accelerate at the same rate, which can be calculated using Newton's second law.
- Determining the time (t1) for block B to hit the floor involves using the kinematic equations, taking into account that block B starts h above the floor and has an initial velocity of 0.
- The motion of block A from t = 0 to the time block B strikes the floor is a constant acceleration to the right, the same as the acceleration of block B downwards.
- After block B strikes the floor, it no longer affects the motion of block A, so block A will continue to move with the velocity it had just before block B hit the floor until it reaches the edge of the table.
- The distance between the landing points of the two blocks can be found by analyzing the projectile motion of block A after it leaves the table and comparing it to the position where block B landed.