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What is the final temperature (in °C) of 150.1 g of water (specific heat = 4.184 J/g°C) at 24.20°C that absorbed 950.0 J of heat?

A) 28.5
B) 29.2
C) 26.8
D) 27.6

1 Answer

3 votes

Final answer:

To find the final temperature of the water, we can use the formula: q = mcΔT, where q is the heat absorbed by the water, m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature. Plugging in the given values, we can solve for the final temperature.

Step-by-step explanation:

To find the final temperature of the water, we can use the formula:

q = mcΔT

where:

  • q is the heat absorbed by the water
  • m is the mass of the water
  • c is the specific heat of water
  • ΔT is the change in temperature

Plugging in the given values:

  • m = 150.1 g
  • c = 4.184 J/g°C
  • ΔT = 24.20°C - initial temperature
  • q = 950.0 J

we can solve for the final temperature

User Kiahni
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