Question

Anyone know the answer to this

Answer 1

Part A:

- angle ACB= 60° (ABC equilateral triangle.)

- Angle ECD=EDC= (180°-32°)/2= 148/2= 74° (sum of angles in a triangle is equal to 180, and triangle ECD is isosceles since it's given that CE=DE.

- x= 180°-(60°+74°)

= 180°-134°

= 46°

x= 46°

Part B:

120°