Question

Write the

slope-intercept form of an equation for
the line of fit. Use points (15, 40) and (41, 61).

Answer 1

Explanation:

Hailey so many people ask about this type of question. I've got a cut and paste answer. I would like to hear from you , posted in the comments of this problem. what's the part of this type of problem that you find complex and difficult. The math to do this is not hard. But it is a difficult problem for so many people. please write in your words what it is that you find difficult. Thanks :)

They ask for slope-intercept form of the problem. this form: y= mx + b

recall there is also point-slope form of y -y1 = m(x -x1)

They give us two points.

point P1 (15,40) in the form (x1,y1)

point P2(41,61) in the form (x2,y2)

Step1: find the slope

slope = m

m = (y2-y1) / (x2-x1)

m= (61-40) / (41-15)

m = 19 / 26

Step 2: now use the point-slope form to get the slope-intercept form. Any given point will work, I'll use P1

y - y1 = m(x -x1)

y - 40 =
`(19)/(26)`(X - 15 )

use your algebra skillz to solve for "Y" ( get "Y" by itself )

y - 40 =
`(19)/(26)`X -
`(19)/(26)`*15

y - 40 =
`(19)/(26)`X -
`(285)/(26)`

y - 40 =
`(19)/(26)`X - 10
`(25)/(26)`

Y =
`(19)/(26)`X - 10
`(25)/(26)` + 40

Y =
`(19)/(26)`X + 30
`(25)/(26)` this is in slope-intercept form now