Final answer:
To find the probability that the sample proportion of adults with hypertension is greater than 5%, we need to use the concept of sampling distribution of proportions. The probability is essentially 0.
Step-by-step explanation:
To find the probability that the sample proportion of adults with hypertension is greater than 5%, we need to use the concept of sampling distribution of proportions. Given that 47% of adults have hypertension according to the CDC, we can assume that the population proportion is 0.47. The standard deviation of the sampling distribution is given by:
sqrt((p * (1-p))/n) = sqrt((0.47 * 0.53)/500) = 0.021
Using the Central Limit Theorem, we can approximate the sampling distribution as a normal distribution. To find the probability that the sample proportion is greater than 5%, we standardize the value:
Z = (0.05 - 0.47)/0.021 = -19.05
Looking up the z-score in a standard normal distribution table or using a calculator, we find that the probability is essentially 0 (very close to 0).