Answer:x=12
y=−186
Step-by-step explanation:x=63x+4y=12
Consider the first equation. Subtract 63x from both sides.
x−63x=4y
Combine x and −63x to get −62x.
−62x=4y
Divide both sides by −62.
x=−
62
1
×4y
Multiply −
62
1
times 4y.
x=−
31
2
y
Substitute −
31
2y
for x in the other equation, 63x+4y=12.
63(−
31
2
)y+4y=12
Multiply 63 times −
31
2y
.
−
31
126
y+4y=12
Add −
31
126y
to 4y.
−
31
2
y=12
Divide both sides of the equation by −
31
2
, which is the same as multiplying both sides by the reciprocal of the fraction.
y=−186
Substitute −186 for y in x=−
31
2
y. Because the resulting equation contains only one variable, you can solve for x directly.
x=−
31
2
(−186)
Multiply −
31
2
times −186.
x=12
The system is now solved.
x=12,y=−186