Question

A connonball is launched from the ground of 30 degrees above the horizontal and a speed of 30 m/s. what is the vertical velocity of the cannonball at the top of its path? (neglect air resistance)

Answer 1

The vertical velocity of the cannonball at the top of its path is approximately 15 m/s.

Step-by-step explanation:

To determine the vertical velocity of the cannonball at the top of its path, we need to consider the motion of the projectile. Since the cannonball is launched at an angle of 30 degrees above the horizontal, the initial velocity can be split into horizontal and vertical components. The vertical component of velocity at the top of the path can be found using the equation:

vvertical = v * sin(θ)

where v is the initial velocity of the cannonball and θ is the launch angle. Plugging in the values:

vvertical = 30 m/s * sin(30°)

vvertical ≈ 15 m/s

Therefore, the vertical velocity of the cannonball at the top of its path is approximately 15 m/s.