Final answer:
The solution contains approximately 1.775 moles of FeCl₂, calculated using its mass and molar mass. The molar concentration of FeCl₂ is roughly 3.944 M, calculated by dividing the number of moles by the volume in liters.
Step-by-step explanation:
To determine the number of moles of FeCl₂ in the solution, we start by calculating the molar mass of FeCl₂, which is 126.75 g/mol. Then, using the mass of FeCl₂ provided (225 g), we can use the formula number of moles = mass (g) / molar mass (g/mol) to find the number of moles present in the solution:
Number of moles = 225 g / 126.75 g/mol
Number of moles = 1.775 moles (to three decimal places)
Note that this calculation is for FeCl₂, even though the question mentioned CaCl₂; this seems to be a typo, as the mass and molar mass given are for FeCl₂.
It is also worth noting that the solution's volume is not used in determining the number of moles, only in calculating the concentration. However, you've asked for the molar concentration, which would be calculated using the formula:
Molar concentration (M) = number of moles / volume (L)
Since the volume is given in mL, we must convert this to liters by dividing by 1000. Therefore, to find the molarity,
Molar concentration = 1.775 moles / 0.450 L
The molar concentration of the solution is thus calculated to be approximately 3.944 M.