The coordinates are: D is
, E is
, F is

To find the coordinates of points D, E, and F which are midpoints of the sides of
, we can use the midpoint formula. The midpoint formula for a line segment with endpoints
and
is given by:
![\[ \left((x_1 + x_2)/(2), (y_1 + y_2)/(2)\right) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/mqshj73ys0txxwozv9dwe60z4b2xfog2ra.png)
Let's apply this formula to find the coordinates:
1. Coordinates of D (midpoint of side AC):
![\[ D = \left((x_A + x_C)/(2), (y_A + y_C)/(2)\right) = \left((-5 + (-3))/(2), (2 + (-6))/(2)\right) = (-4, -2) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/azphlb0y09hfkhkojesc5beo46v42inb0y.png)
2. Coordinates of E (midpoint of side AB):
![\[ E = \left((x_A + x_B)/(2), (y_A + y_B)/(2)\right) = \left((-5 + 1)/(2), (2 + (-2))/(2)\right) = (-2, 0) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/ge92u2rbim0np0s7g1jtmz6m38ure4i5w0.png)
3. Coordinates of F (midpoint of side BC):
![\[ F = \left((x_B + x_C)/(2), (y_B + y_C)/(2)\right) = \left((1 + (-3))/(2), ((-2) + (-6))/(2)\right) = (-1, -4) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/t3uwnq0jkhoxuzpe6w7y9ravcz0n0s2ths.png)
So, the coordinates are:
- D is

- E is

- F is

The probable question may be: "Use the graph of $\triangle ABC$ with midsegments $\overline{DE},\ \overline{EF},\ $ and $\overline{DF}$. Find the coordinates of points D, E, and F.
A triangle is drawn on coordinate plane. The x-axis is extended from negative 6 to 2, in increments of 2. The y-axis is extended from negative 6 to 2, in increments of 2. Vertex A lies at the ordered pair negative 5 comma 2. Vertex B lies at the ordered pair 1 comma negative 2. Vertex C lies at the ordered pair negative 3 comma negative 6. E is the midpoint of side A B. D is the midpoint of side A C. F is the midpoint of side B C. Segments D E, E F, and D F are the mid-segments. Find the coordinates of point D,E,F"