Question

Billiard ball A of mass m = 0.116 kg moving with speed = 2.80 m/s strikes ball B, initially at rest, of mass mp = 0.144 kg. As a result of the collision, ball A is deflected off at an angle of =30.0° with a speed v = 2.10 m/s, and ball B moves with a speed up at an angle of 0 to original direction of motion of ball A.

Taking the x axis to be the original direction of motion of ball A, choose the correct equation expressing the conservation of momentum for the components in the x direction.
a. 0 = mAvA sin θ - mBvB Sin θB
b. mAvA = mAvA cos θA + mBvB cos θB
c. 0 = (MAVA+MBV) sin
d. MAVA = MAVA COSθA - mBvB θB

Answer 1

The correct equation expressing the conservation of momentum for the components in the x direction is 0 = mAvAsin(θ) - mBvBsin(θB).

Step-by-step explanation:

The correct equation expressing the conservation of momentum for the components in the x direction is:

0 = mAvAsin(θ) - mBvBsin(θB)

Where:

• mA is the mass of ball A
• mB is the mass of ball B
• vA is the velocity of ball A in the x direction
• vB is the velocity of ball B in the x direction
• θ is the angle at which ball A is deflected off
• θB is the angle at which ball B moves with respect to the original direction of motion of ball A