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Solve the trigonometric equation on the interval 0 ≤ theta < 2 (Enter your answers as a comma-separated list.)

2 sin(theta) − √2 = 0
theta = ??

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Final answer:

To solve the trigonometric equation 2sin(theta) - sqrt(2) = 0 on the interval 0 ≤ theta < 2, we isolate sin(theta) by adding sqrt(2) to both sides and then dividing by 2. The solution is theta = 45 degrees, 135 degrees.

Step-by-step explanation:

To solve the trigonometric equation 2sin(theta) - sqrt(2) = 0 on the interval 0 ≤ theta < 2, we need to isolate sin(theta). Start by adding sqrt(2) to both sides of the equation to get 2sin(theta) = sqrt(2). Then, divide both sides by 2 to get sin(theta) = sqrt(2)/2. So theta can be determined using the inverse sine function: theta = sin¯¹(sqrt(2)/2).

Since sin¯¹(sqrt(2)/2) equals 45 degrees or π/4 radians, theta can be equal to either 45 degrees or 135 degrees. However, we need to find the values of theta on the interval 0 ≤ theta < 2. Therefore, the solution to the equation is theta = 45 degrees, 135 degrees.

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