Final answer:
To determine which frequency matches the wavelengths given for mercury atoms, we use the relationship c = λν and calculate the frequency for each provided wavelength. The only frequency from the choices that corresponds to one of these wavelengths (365 nm) is 8.2 × 10¹⁴ s⁻¹. option C
Step-by-step explanation:
To find out which frequency is emitted by mercury atoms, we can use the formula for the speed of light (c) which relates wavelength (λ) and frequency (ν) by the equation c = λν. Since the speed of light is a constant (c = 3.00 × 108 m/s), we can rearrange the equation to solve for frequency: ν = c/λ.
Let’s solve for each wavelength given in the question:
For λ = 185 nm (which is 185 × 10-9 m), ν = 3.00 × 108 m/s ÷ 185 × 10-9 m ≈ 1.62 × 1015 s-1
For λ = 254 nm, ν ≈ 1.18 × 1015 s-1
For λ = 365 nm, ν ≈ 8.22 × 1014 s-1
For λ = 436 nm, ν ≈ 6.88 × 1014 s-1
For λ = 546 nm, ν ≈ 5.49 × 1014 s-1
For λ = 615 nm, ν ≈ 4.88 × 1014 s-1
The only frequency that matches an option given by the question is 8.22 × 1014 s-1, corresponding to the 365 nm wavelength, so the correct answer is c. 8.2 × 1014 s-1.