Final answer:
The maximum number of moles of H₂ that can be produced from the reaction of 3.00 mol of Ni with 4.50 mol of HCl is 2.25 mol, as HCl is the limiting reagent in the chemical equation Ni + 2HCl → NiCl₂ + H₂.
Step-by-step explanation:
The student is asking about the maximum number of moles of H₂ that can be produced from the reaction of 3.00 mol of Ni with 4.50 mol of HCl. According to the balanced chemical equation Ni + 2HCl → NiCl₂ + H₂, the mole ratio of Ni to HCl is 1:2. This means it takes 2 moles of HCl to react completely with 1 mole of Ni to produce 1 mole of H₂.
Since there are 3.00 mol of Ni available, it would require 6.00 mol of HCl to react completely with the Ni; however, there are only 4.50 mol of HCl available. Therefore, HCl is the limiting reagent. Based on the mole ratio, the maximum amount of H₂ that can be produced from the available HCl is 2.25 mol (since 4.50 mol HCl would produce 2.25 mol H₂).